[Python] Il dilemma degli array mutabili
Nicola Larosa
nico a tekNico.net
Gio 19 Set 2013 17:11:50 CEST
> Piergiuliano Bossi ha scritto:
>> def useless(list):
>> return [list[i] for i in range(len(list)) if evaluate(list[:i] +
>> list[i+1:]) == evaluate(list)]
Marco Beri wrote:
> Questo codice può diventare un più chiaro con enumerate:
>
> def useless(list):
> return [val for i, val in enumerate(list) if evaluate(list[:i] +
> list[i+1:]) == evaluate(list)]
Meglio non usare "list" come nome, perchè copre il builtin.
--
Nicola Larosa - http://www.tekNico.net/
I'll play closed-source games because they're not very harmful, and
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